ciagi szarlotka: Oblicz granice ciągów;

	(−1)n
cn = n√		+ 2n (calosc pod pierwiastkem)
	n

	[n√2]
dn =
	[n√3]

	1		2		n
en = n(		+		+...+		)
	n2 +1		n2 +2		n2+n

	[√2n]
gn =
	n

h_n = log_n+1 (n² + 1)

	1
an = (1 +		)3n
	n+2

Janek191:

	(−1)n
cn = n√(		+ 2 n)
	n

	−1		1
an = n√ (		+ 2n) bn = n√ (		+ 2n)
	n		n

więc a_n ≤ c_n ≤ b_n i lim a_n = 1 i lim b_n = 1 n→∞ n→∞ więc na mocy tw. o trzech ciągach lim c_n = 1 n→∞