H | ||
tg α = | ||
x |
1 | ||
z tresci polecenia tg α = | zatem | |
2 |
1 | H | ||
= | |||
2 | x |
2 | a√3 | |||
x = | h, gdzie h = | (wysokosc trojkata rownobocznego) | ||
3 | 2 |
2 | a√3 | a√3 | ||||
x = | * | = | ||||
3 | 2 | 3 |
3x | ||
a = | = x√3 | |
√3 |
1 | a2√3 | |||
V = | * | * H = ... = 4096√3 | ||
3 | 4 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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