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alal: √6z + √3 = √12 − √3z
20 wrz 18:25
Jack: √12 = 2
√3 , zatem :
√6z +
√3 = 2
√3 −
√3z
√6z +
√3z =
√3
z(
√6 +
√3) =
√3
| | √3 | | √3 | | √6 − √3 | |
z = |
| = |
| * |
| = |
| | √6 + √3 | | √6 + √3 | | √6 − √3 | |
| | √3(√6−√3) | | √18 − 3 | | 3√2 − 3 | | 3(√2−1) | |
= |
| = |
| = |
| = |
| = √2−1 |
| | 6 − 3 | | 3 | | 3 | | 3 | |
20 wrz 18:33