oblicz
karko: 8sin280o−2√3sin40o−2cos40o=
17 lip 23:31
Mila:
8sin
2(80)−2
√3sin(40)−2cos(40)=
| √3 | | 1 | |
=4*[2sin2(80)−( |
| sin(40)+ |
| cos(40))]= |
| 2 | | 2 | |
=4*[2sin
2(80)−(sin(40)*cos(30)+sin(30)*cos(40))]=
=4*[2sin
2(80)−sin(30+40)]==4*[2sin
2(80)−sin(70)]=
=4*[2sin
2(80)−cos20]=4*[2cos
2(10)−cos20]=
| cos(20)+1 | |
=4*[2* |
| −cos20]= |
| 2 | |
=4*[cos(20)+1−cos(20)]=4
18 lip 00:15
Niki: 5+3
18 lip 09:51