| 1 | |
∫arctgt dt= przez części | |
| 4 |
| 1 | ||
[arctgt=u, | dt=du, dv=1dt, v=∫1dt=t] | |
| t2+1 |
| 1 | t | |||
= | *[t*arctgt−∫ | dt]= | ||
| 4 | t2+1 |
| 1 | 1 | |||
= | *[t*arctgt− | ln(t2+1)]= | ||
| 4 | 2 |
| 1 | 1 | |||
= | *[4xarctg(4x)− | ln(16x2+1]= | ||
| 4 | 2 |
| 1 | ||
=xarctg(4x)− | ln(16x2+1)+C | |
| 8 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |