| (1−50r)(1−2r) | ||
moglby mi ktos obliczyc pochodna z tej funkcji : f(x)= | ||
| 1−r |
| 100r2+148r−51 | ||
Mi ciagle wychodzi f(x)'= | , a powinno wyjsc: | |
| (1−r)2 |
| −100r2+200r−51 | |
| (1−r)2 |
| 100r2−52r+1 | ||
f(x)= | ||
| 1−r |
| (200r−52)(1−r)+100r2−52r+1 | 200r−200r2−52+52r+100r2−52r+1 | |||
f'(x)= | = | |||
| (1−r)2 | (1−r)2 |
