Oblicz logarytm
konopnicka: Jeśli a= 3√2 i b= (18−4 / 3−8)*(2√2)4, to log małe b (w podstawie) a jest równy
22 lut 20:50
Janek191:
| | 18−4 | | 18−4 | |
b = |
| *(2√2)4 = |
| *16*4 = 2−4*26 = 22 = 4 |
| | 3−8 | | 9−4 | |
| | 1 | | 1 | | 1 | | 1 | |
logb a = log4 3√2 = log4 213 = |
| log4 2 = |
| * |
| = |
| |
| | 3 | | 3 | | 2 | | 6 | |
22 lut 20:57
konopnicka: Dziękuję Janek191
22 lut 21:01