Uzasadnij, że Karina: Uzasadnij, że jeżeli f(x) = x(x−1)(x−2)(x−3)(x−4)(x−5), to f'(0) = −1(−2)(−3)(−4)(−5) = −120

jc: Wyraz przy x do potegi 1 to (−1)(−2)(−3)(−4)(−5) = −120, i tyle wynosi pochodna w punkcie 0.

Bogdan: f(x) = x * [(x−1)(x−2)(x−3)(x−4)(x−5)] f'(x) = 1 * [(x−1)(x−2)(x−3)(x−4)(x−5)] + x * [(x−1)(x−2)(x−3)(x−4)(x−5)]' f'(0) = (−1)(−2)(−3)(−4)(−5) + 0 * [(x−1)(x−2)(x−3)(x−4)(x−5)]' = −120