| 1 | 1 | |||
Wiedzac że x+ | =3 oblicz wartość wyrażenia |x− | | | ||
| x | x |
| 1 | ||
x+ | =3 | |
| x |
| 1 | ||
(x+ | )2 = 9 | |
| x |
| 1 | 1 | |||
x2 + 2*x* | + | = 9 | ||
| x | x2 |
| 1 | ||
x2 + 2 + | = 9 | |
| x2 |
| 1 | ||
x2 + | = 7 | |
| x2 |
| 1 | ||
x+ | =3 | |
| x |
| 1 | ||
|x− | |= √(x−1x)2=√(x+1x)2−4= √32−4= √5 | |
| x |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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