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qqq sss: 3√−4 |z| = 4 cosφ = −1 sinφ = 0 II ćwiartka φ = π − α0 = π − 0 = π
  π+2*0*π   π+2*0*π  
ω0 = 3√4( cos
+ isin
) =
  3   3  
  π   π   1   √3  
3√4( cos
+ isin
) = 3√4(
+
i )
  3   3   2   2  
  π+2*1*π   π+2*1*π  
ω1 = 3√4( cos
+ isin
) =
  3   3  
3√4( cosπ + isinπ ) = 3√4( cos(π + 0) + isin(π + 0) ) = 3√4( −cos0 − isin0 ) = −3√4
  π+2*2*π   π+2*2*π  
ω2 = 3√4(cos
+ isin
) =
  3   3  
  5   5  
3√4( cos
π + isin
π ) =
  3   3  
  π   π  
3√4( cos(2π −
) + isin(2π −
) ) =
  3   3  
  π   π  
3√4( cos
+ isin
) =
  3   3  
  1   √3  
3√4(
−
i
  2   2  
?
7 lut 19:59