| ex | ||
−1∫2 | dx = ... | |
| ex+1 |
| ex | ||
∫ | dx = | ex+1 = t , exdx = dt | = | |
| ex+1 |
| 1 | ||
∫ | dt = ln|t|+C = ln|ex+1| + C | |
| t |
| 1 | ||
... −1[ln|ex+1|]2 = ln|e2+1| − ln| | + 1| | |
| e |
dzięks
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |