wyrazenia wymierne olaa: jak to rozwiazac? (50x²−18)² : (3+5x)(5x−3) ? dla x = − 1/5 robilam (2(25x²−9))² : (5x+3)(5x−3) = (2(5x−3)(5x+3))² : (5x+3)(5x−3) i jak to teraz skrocic?

Jack: (50x²−18)² = (2(25x²−9))² = (2(5x−3)(5x+3))² = 4(5x−3)²(5x+3)²

olaa: i z tego 4(5x−3)²(5x+3)² : (5x+3)(5x−3) juz sie nie da bardziej uproscic?

Mila:

(50x2−18)2
	=
(3+5x)(5x−3)

	[2*(25x2−9)]2
=		=
	(5x+3)*(5x−3)

	4*(5x−3)2*(5x+3)2
=		=
	(5x+3)*(5x−3)

=4*(5x+3)*(5x−3)}

	1		1		1
W(−		)=4*(5*(−		)+3)*(5*(−		)−3)=
	5		5		5

=4*(−1+3)*(−1−3)

Jack: podziel ; d

4(5x−3)2(5x+3)2
	= 4(5x−3)(5x+3)
(5x+3)(5x−3)