| 2x | ||
Napisac rownanie stycznej do wykresu funkcji f(x)= | w punkcie (√2,f(√2) | |
| 1 + x2 |
| 2 | 8√2 | |||
Mam odpowiedz y=− | + | |||
| 9 | 9 |
| 2 | ||
mala poprawka − | x | |
| 9 |
| 2√2 | 2√2 | |||
f(√2)= | = | |||
| 1+2 | 3 |
| 2*(1+x2)−2x*2x | ||
f'(x)= | ||
| (1+x2)2 |
| 2−2x2 | ||
f'(x)= | ||
| (1+x2)2 |
| 2 | ||
f'(√2)=− | ||
| 9 |
| 2 | ||
s: y=− | x+b | |
| 9 |
| 2√2 | 2 | ||
=− | *√2+b | ||
| 3 | 9 |
| 8√2 | ||
b= | ||
| 9 |
| 2 | 8√2 | |||
s: y=− | x+ | |||
| 9 | 9 |