| dx | ||
∫ | ||
| √x+23√x2 |
| 6t2 | ||
podstawienie: t = 6√x , t6 = x , 6t5dt = dx ...... = ∫ | dt | |
| t3 + 2t4 |
| 6t2 | ||
= ∫ | dt | |
| 2t + 1 |
| 1 | ||
podstawienie: u=6√x, du= | ||
| 6x5/6 |
| u5 | ||
wtedy będzie 6∫ | du | |
| 2u4+u3 |
| 6t5 | 6t2 | |||
= ∫ | dt = | dt | ||
| t3 + 2t4 | 2t + 1 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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