kąt DAB = 30 stopni
Pole ABCD = 22
Oblicz pole i obwód figury f
| 55 | ||
Pf= | [j2] | |
| 3 |
| √11 | ||
Lf= | (12−π) [j] | |
| 3 |
| 11 | ||
Pf= | (6−π) [j2] | |
| 3 |
| 1 | 11 | |||
P(wycinka BAD)= | πr2= | π | ||
| 12 | 3 |
| 11 | ||
Pf= 22− | π = .... | |
| 3 |
| 1 | √11 | |||
Lf= 2r+ długość łukuBD |łukuBD|= | *2πr= | π | ||
| 12 | 3 |
| √11 | ||
Pf= | (6−π) | |
| 3 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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