Podaj twierdzenie dotyczace dzialan na potegach. Oblicz.
Mateuszz: 3√27*9−1,5*(13)0,75*(181)−2
8 gru 17:22
M:
2 cze 06:29
Fuyao:
3=3
1
√27=
√9*3=
√9*
√3=3
√3=3
1*3
1/2=3
1,5
9
−1,5=(3
2)
−1,5=3
−3
| | 1 | |
( |
| )0,75=(3−1)0,75=3−0,75 |
| | 3 | |
| | 1 | | 1 | |
3√27*9−1,5*( |
| )0,75*( |
| )−2= |
| | 3 | | 81 | |
=3
1*3
1,5*3
−3*3
−0,75*3
8=
=3
1+1,5−3−0,75+8=3
6,75=3
27/4=
4√327
2 cze 19:27