23 lis 22:21
Janek191:
| | x2 + 15 | | x2 + 15 | |
log2 |
| = 3 ⇔ 23 = |
| |
| | x | | x | |
8 x = x
2 + 15
x
2 − 8 x + 15 = 0
Δ = 64 − 60 = 4
| | 8 − 2 | | 8 +2 | |
x = |
| = 3 lub x = |
| = 5 |
| | 2 | | 2 | |
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23 lis 22:29
sushi_gg6397228:
dziedzina a potem z definicji
loga b= c <=> ac=b
23 lis 22:30
Tadeusz:
x>0
i z definicji
23 lis 22:30