nie pomagać knt: nie pomagać z⁵=(cos(^π₁₅)−isin(^π₁₅))⁵ |z|=√cos²(^π₁₅)+sin²(^π₁₅)=1 cosφ=cos(^π₁₅) sinφ=−sin(^π₁₅) → φ należy do IV ćw. → 2π−^π₁₅ = ^29π₁₅ z⁵=1⁵(cos5*(^29π₁₅)+isin5*(^29π₁₅))=cos(^29π₃)+isin(^29π₃) =cos(9π+^2π₃)+isin(9π+^2π₃)=cos(π+^2π₃)+isin(π+^2π₃)= −cos(^2π₃)−isin(^2π₃)=−cos(π−^π₃)−isin(π−^π₃)= cos(^π₃)−isin(^π₃)=¹₂−i^√3₂

	1		√3
Odp. z5 =		− i
	2		2

romek: