| 2−3√x+8 | ||
Oblicz granicę funkcji: lim x→0 | ||
| x |
| 2−3√x+8 | ||
lim x→0 | = | |
| x |
| (2−3√x+8)(22+23√x+8+(3√x+8)2) | ||
= lim x→0 | = | |
| x(22+23√x+8+(3√x+8)2) |
| 23−(3√x+8)3 | ||
= lim x→0 | = | |
| x(22+23√x+8+(3√x+8)2) |
| 8−x−8 | ||
= lim x→0 | = | |
| x(4+23√x+8+(3√x+8)2) |
| −x | ||
= lim x→0 | = | |
| x(4+23√x+8+(3√x+8)2) |
| −1 | −1 | |||
= lim x→0 | = | = | ||
| 4+23√x+8+(3√x+8)2 | 4+23√8+(3√8)2 |
| −1 | −1 | |||
= | = | = − 112 . ...  | ||
| 4+2*2+(2)2 | 3*4 |