| 1 | ||
Czy | ma rozkład na ułamki proste | |
| x2(x+1) |
| 1 | A | B | C | ||||
= | + | + | |||||
| x2(x+1) | x | x2 | x+1 |
| 1 | −1 | 1 | |||
= | + | +U{1}{x+1| | |||
| x2(x+1) | x | x2 |
| −1 | 1 | 1 | −x−1+x | 1 | −1 | 1 | |||||||
+ | + | = | + | = | + | ||||||||
| x | x+1 | x2 | x(x+1) | x2 | x(x+1) | x2 |
| −x2 + x2+x | 1 | ||
= | |||
| x(x+1)x2 | x2(x+1) |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
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| Twój nick | |