| ln(1−tg2x | ||
11) lim(xdo0) | ||
| x2 |
| xcosx−sinx | ||
12) lim(xdo0) | ||
| sinx−x |
| 1 | ||
18) lim9xdoniesk) xln(1+sin | ) | |
| x |
| −2tgx | −tgx | |||
1) = [H] ... lim | = lim | = [H] | ||
| 2x(1−tg2x)cos2x | x*cos2x |
| −1 | |||||||||
= | = [ | ] = − 1 | ||||||||
| cos2x − 2xsin2x | 1 |
| − xsinx | sinx + xcosx | |||
2) = ..[H] .. lim | = ...[H] ... lim [ − | ] | ||
| cosx − 1 | −sinx −1 |
| 0 | ||
= [− | ] = 0 | |
| 1 |
| ||||||||
18) = lim | = | |||||||
| (−1/x2) |
| cos(1/x) | 1 | |||
= lim | = [ | ] = 1 | ||
| 1 + sin(1/x) | 1 |
| π | ||
15) ....dobrze przepisane ? ... jeśli tak, to wprost: .. = [ | *∞] +∞ | |
| 2 |
| π | ||
zjadłem znak "=" ... = [ | * ∞] = +∞ | |
| 2 |