| a + b | a | b | ||||
Podpowiedź: | = | + | ||||
| c | c | c |
| 2xcos2x + 1 | ||
∫ | dx | |
| cos2x |
| 1 | ||
tak jak napisał Bogan oraz ( | )'=tgx | |
| cos2x |
| 1 | ||
[tg(x)]' = | ||
| cos2(x) |
| 2xcos2x | 1 | 2xcos2x | ||||
∫ | +∫ | = ∫ | + tgx wydaje mi się, że tak to | |||
| cos2x | cos2x | cos2x |
| a*b | ||
Podpowiedź (ech, student) | = a dla b≠0 | |
| b |
| dx | cos2(x)+sin2(x) | |||
∫ | =∫ | dx | ||
| cos2{x} | cos2(x) |
| sin(x) | sin(x) | cos(x) | ||||
∫dx+∫sin(x) | dx=∫dx+ | −∫ | dx | |||
| cos2(x) | cos(x) | cos(x) |
| dx | sin(x) | |||
∫ | = | +C | ||
| cos2{x} | cos(x) |