| b−a | b | b−a | ||||
<ln | < | 0<a<b | ||||
| b | a | a |
| 1 | ||
f'(x)= | ||
| x |
| f(b)−f(a) | ||
Z twierdzenie Lagrange'a | =f'(c), gdzie a<c<b | |
| b−a |
| lnb−lna | 1 | ||
= | /*(b−a) | ||
| b−a | c |
| b−a | ||
lnb−lna= | ||
| c |
| b | b−a | |||
ln | = | , | ||
| a | c |
| b−a | b | b−a | ||||
Ponieważ a<c<b, to | <ln | < | ||||
| b | a | a |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |