f(3 + h) − f(3) | √6(3 + h) + 1 − √19 | |||
f'(3) = limh→0 | = limh→0 | = | ||
h | h |
√19 + 6h − √19 | ||
= limh→0 | = | |
h |
19 + 6h − 19 | ||
= limh→0 | = | |
h(√19 + 6h + √19) |
6 | 6 | |||
= limh→0 | = | |||
√19 + 6h + √19 | 2√19 |
6 | 3 | |||
f'(x) = | = | |||
2√6x+1 | √6x+1 |
3 | ||
f'(3)= | ||
√19 |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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