| 2(1+m) | ||
Niech m=log2 3. Wykaż, że log3 36= | ||
| m |
| 1 | ||
= 2*( log3 3 + log3 2) = 2*( 1 + | ) = | |
| log2 3 |
| 1 | 2*( 1 + m) | |||
= 2*( 1 + | ) = | |||
| m | m |
| 1 | 1 | 2(1+m) | ||||
log336= log39+log34 = 2+2log32= 2(1+ | )= 2(1+ | )= | ||||
| log23 | m | m |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
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