| a1 | ||
Sn = | ||
| 1 − q |
| 1 | ||
Zauważmy, że ∑ | =1/2+1/6+1/12+1/20+... | |
| k(k+1) |
| 1 | (k+1)−k | 1 | 1 | ||||
= | = | − | |||||
| k(k+1) | k(k+1) | k | k+1 |
| 1 | 1 | 1 | ||||
Czyli ∑ | =∑ | − | ta suma się teleskopuje | |||
| k(k+1) | k | k+1 |
| 1 | 1 | |||
∑ | − | =(1−1/2)+(1/2−1/3)+(1/3−1/4)+...=1 | ||
| k | k+1 |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
|---|---|
| Twój nick | |