| 2+x | x | |||
Narysuj wykres fukncji f(x)=arctg( | ) − arctg( | ) | ||
| 2−x | 2 |
| (2+x) | x | |||
a = arctg( | ), b = arctg( | ) | ||
| (2−x) | 2 |
| (2+x) | x | ||
= tg(a), | = tg(b) | ||
| (2−x) | 2 |
| tg(a) − tg(b) | ||
tg(a−b) = | = | |
| 1 + tg(a)tg(b) |
| |||||||||||||||||
= | |||||||||||||||||
|
| (2(2+x) − x(2−x)) / 2(2−x) | ||
= 1 | ||
| (2(2−x) + 2x + x2) / 2(2−x) |
| π | ||
f(x) = | dla x ≠ 2 | |
| 4 |