16 | ||
Suma wyrazów nieskonczonego, malejącego ciągu geometrycznego wynosi | . | |
3 |
1 | ||
Jednym z jego wyrazów jest | . Ktory to wyraz, jezeli wiadomo, ze stosunek wyrazow go | |
6 |
1 | ||
ak= | ||
6 |
16 | ||
S= | ||
3 |
a1 | 16 | ||
= | |||
1−q | 3 |
16 | ||
a1= | (1−q) | |
3 |
1 | 16 | |||
Sk− | =30* | −30Sk | ||
6 | 3 |
961 | ||
31Sk= | ||
6 |
31 | ||
Sk= | ||
6 |
1−qk | 31 | |||
a1* | = | |||
1−q | 6 |
16 | 31 | ||
(1−qk)= | |||
3 | 6 |
31 | ||
1−qk= | ||
32 |
1 | ||
qk= | ||
32 |
1 | ||
qk−1= | ||
32q |
1 | ||
a1qk−1= | ||
6 |
16 | 1 | ||
(1−q)*qk−1= | |||
3 | 6 |
16 | 1 | 1 | |||
(1−q)* | = | ||||
3 | 32q | 6 |
1−q | 1 | ||
= | |||
6q | 6 |
1 | ||
q= | ||
2 |
1 | 1 | |||
( | )k−1= | |||
2 | 32*12 |
1 | 1 | |||
( | )k−1= | |||
2 | 16 |
1 | ||
a5= | ||
6 |