tg
Ned Stark: Kąt α jest ostry oraz tgα x tg19 = 1. Ile wynosi α?
22 mar 22:26
ICSP: | | 1 | |
tgα = |
| = ctg19 = tg(90 − 19) = tg71 |
| | tg19 | |
α = 71
22 mar 22:32
Janek191:
tg α *tg 19o = 1
więc
tg α = ctg 19o = ctg ( 90o − 61o) = tg 61o
α = 61o
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22 mar 22:33
Janek191:
Oczywiście 71
o 
22 mar 22:34
Ned Stark: dziękować
22 mar 22:36