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rownania trygonometryxzne monika: a) 3cosx=3cos2x−2sin2xcosx b) 3cos2x+9cosx+43=0
16 lut 21:08
pigor: ..., np. tak : a) 3cosx = 3cos2x−2sin2xcosx ⇔ 3cosx = 3cos2x−2cosx(1−cos2x) ⇔ ⇔ 3cosx = 3cos2x−2cosx+2cos3x ⇔ 2cos3x+3cos2x−5cosx = 0 ⇔ ⇔ cosx (2cos2x+3cosx−5) = 0 ⇔ cosx (2cos2x−2cosx+5cosx−5) = 0 ⇔ ⇔ cosx=0 v 2cos2x−2cosx+5cosx−5 = 0 ⇔ ⇔ x=12π+kπ, k∊C v 2cosx(cosx−1)+5(cosx−1)=0 ⇒ (cosx−1)(2cosx+5)=0 ⇔ ⇔ cosx−1=0 v x∊∅ ⇒ cosx=1x=2kπ, k∊C . ...emotka
16 lut 21:37
pigor: ..., np. tak : b) 3cos2x+9cosx+43= 03(2cos2x−1)+9cosx+43= 0 ⇔ ⇔ 23cos2x+9cosx+33= 0 /:3 ⇔ 2cos2x+33cosx+3= 0 ⇔ ⇔ 2cos2x+23cosx+3cosx+32=0 ⇔ 2cosx(cosx+3)+3(cosx+3)=0 ⇔ ⇔ (cosx+3) (2cosx+3)=0 ⇔ x∊∅ v 2cosx+3=0 ⇒ cosx= −123 ⇔ ⇔ x= −16π+2kπ v x= π+16π+2kπ ⇔ ⇔ x= 116π+2kπ v x= 76π+2kπ , k∊C . ...emotka
16 lut 21:55