oblicz pochodną wiciu: pochodna z (x+1)² e^−z

Janek191: f(x) = ( x + 1)² e^−x = ( x² + 2 x + 1) e^−x więc f '(x) = ( 2 x + 2) e^−x + ( x² + 2 x + 1) e^−x *(−1) = = ( 2 x + 2) e^−x − ( x² + 2 x + 1) e^−x = ( − x² + 1) e^−x