Siemanko,podpwoiecie jak zrobić ten logarytm
YOYO: 1−log[24]3log[24]2
[24] to podstawa logarytmu
4 sty 17:33
Eta:
1= log
2424
| | log2424−log243 | | | |
...= |
| = |
| = |
| | log242 | | log242 | |
| | log248 | |
= |
| =log28= 3 |
| | log242 | |
4 sty 17:38
YOYO: Aha czyli ta 1 to po prostu log[24]24 ^^
4 sty 17:41
Eta:
| | 1 | |
2 sposób taki: |
| = logba |
| | logab | |
| | 1 | | log243 | | 24 | |
...= |
| − |
| = log224−log23= log2 |
| = log28=3 |
| | log242 | | log242 | | 3 | |
4 sty 17:45