karo_linka: logx-1/2log(x-1/2)=log(x+1/2)-1/2log(x+1/8) log(3x²+7)-log(3x-2)=1 log_x2-log₄x+7/8=0 log₁₆x+log_2x x+log₂ x =2/3 log_1-x 3-log_1-x 2 -0,5=0