| 1−log23 3 | |
=log23 | |
| (log23+log32+1)*log223 |
| 1 | 1 | |||
(log23+ | +1)(1−log23)=log23+ | +1−log223−1−log23= | ||
| log23 | log23 |
| 1 | ||
teraz w mianowniku , log32= | i log2(2/3)= 1−log23 | |
| log23 |
| 1 | ||
Mianownik : (log23+ | +1)*(1−log23) = | |
| log23 |
| 1 | 1 | |||
= | ( log223+log23+1) *(1−log23)= | (1−log233) | ||
| log23 | log23 |
| 1−log233 | ||
= | ... tak rozpracowaliśmy mianownik | |
| log23 |
