4x2−9 | |
1,5−x |
(2x−3)(2x+3) | |
= ... | |
−1/2(2x−3) |
3 | 9 | 3 | 3 | |||||
1,5= | i 4x2−9= 4(x2− | )= 4(x− | )(x+ | ) | ||||
2 | 4 | 2 | 2 |
3 | ||
dla x≠ | ||
2 |
| |||||||||||||||||
= ........ | |||||||||||||||||
|
4x2−9 | 2(2x−3)(2x+3) | ||
= | = −2(2x+3) i koniec ... ![]() | ||
1,5−x | 3−2x |
5^2 | 52 |
2^{10} | 210 |
a_2 | a2 |
a_{25} | a25 |
p{2} | √2 |
p{81} | √81 |
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