| 2 | ||
log162√2− 3 | ||
| log5 3 |
| 1 | 2 | |||
log53= | to | = 2log35= log352 | ||
| log35 | log53 |
| 3 | |||||||||
log162√2= log24(23/2)= | log22= | |||||||||
| 4 | 8 |
| 3 | 3 | 1 | 3 | |||||
log162√2 = log1623/2 = | log162 = | * | = | |||||
| 2 | 2 | 4 | 8 |
| 2 | 1 | |||
3 | = 32* | = zmieniam podstawę logarytmu = 32*log35 = | ||
| log53 | log53 |
| 3 | |
− 25 = ... | |
| 8 |
