oblicz granice
magda: Oblicz granice:
a) lim xcos2x/sinx+cosx
x→−π/4
b)lim (1/cosx+tgx)
x→π/2−
18 lis 16:48
pigor: ..., np.
| | xcos2x | |
a) limx→ − π4 |
| = |
| | sinx+cosx | |
| | x(cos2x−sin2x) | |
= limx→ − π4 |
| = |
| | sinx+cosx | |
| | x(cosx−sinx)(cosx+sinx) | |
= limx→ − π4 |
| = |
| | sinx+cosx | |
= lim
x→ − π4 x(cosx−sinx)= −
π4(cosu(−
π4)−sin(−
π4))=
= −
π4(cos
π4+sin
π4)= −
π4√2. ...
=
18 lis 17:08
Metis: pigor możesz zerknąć ?
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18 lis 17:12