trygonometria
Olgaaa: Rozwiąż równanie
5tgx+cos2x+sin2x=1
11 lis 16:19
ICSP: 5tgx + cos
2x + 2sinxcosx = cos
2x + sin
2x
| | sinx | |
5 |
| + 2sinxcosx − sin2x = 0 |
| | cosx | |
| | 5 | |
sinx( |
| + 2cosx − sinx) = 0 |
| | cosx | |
sinx(5 + 2cos
2x − sinxcosx) = 0
sinx = 0
x = kπ , k ∊ Z
11 lis 17:44