granica Kamilek:

	1		1		1
lim n(		+		+...		)
	n2+1		n2+2		n2+n

Janek191:

	1		1		1
an = n*(		+		+ ... +		) =
	n2 + 1		n2 + 2		n2 + n

	n		n		n
=		+		+ ... +
	n2 + 1		n2 + 2		n2 + n

Tw o trzech ciagach :

	n		n		n		n		n2
bn =		+		+ ... +		= n*		=
	n2 + n		n2 + n		n2 + n		n2 + n		n2 + n

	n		n		n		n		n2
cn =		+		+ ... +		= n*		=
	n2 + 1		n2 + 1		n2 +1		n2 + 1		n2 + 1

Mamy zatem b_n ≤ a_n ≤ c_n oraz lim b_n = 1 i lim c_n = 1 n→∞ n →∞ więc z tw. o trzech ciągach lim a_n = 1 n→∞