TRYGONOMETRIA eryk17: Udowodnij tożsamość: sin⁶α +cos⁶α +3sin²αcos²α=1

Eta: a⁶+b⁶= (a²+b²)³ −3a²b−3ab²= (a²+b²)³− 3ab(a²+b²) to: L= (sin²α+cos²α)³−3sin²α*cos²α(sin²α+cos²α) +3sin²α*cos²α= =1−3sin²αcos²α*1+3sin²α*cos²α= 1=P