logorytmy
iza: skoro a=log10002, b=log14 to ile to log5 i log35?
12 cze 15:50
iza: może jednak?
12 cze 18:19
iza: ktoś potrafi?
12 cze 18:20
Godzio:
| | log2 | | 1 | |
log10002 = |
| = |
| log2 |
| | log1000 | | 3 | |
| | 10 | |
log5 = log |
| = log10 − log2 = 1 − 3a |
| | 2 | |
| | 5 | | 5 | |
log35 = log(7 * 5) = log(14 * |
| ) = log14 + log |
| = log14 + log5 − log2 = ... |
| | 2 | | 2 | |
12 cze 18:23
iza: dziękuję!
12 cze 18:33