| 3√n3+4 | ||
3. lim | ||
| 3√8n3−1−4n |
| 1 | ||
limn→oo (n−n4)*2n = limn→oo n4*( | −1)*2n = | |
| n3 |
| 1 | ||
= limn→oo n4*( | −1)*2n = ....... | |
| n3 |
| 1 | ||
x→oo => n4 =  ; | = ; 2n = | |
| n3 |
− gdzie to wszystko dąży
| 3√n3+4 | n*3√1+(4/n3) | |||
limn→oo | = limn→oo | = | ||
| 3√8n3−1−4n | n*(3√8−(1/n3)−4) |
| 3√1+(4/n3) | ||
= limn→oo | = | |
| 3√8−(1/n3)−4 |