Z góry, dziękuję Wam za pomoc
AB=a
DC=b
CK=h
AB||DC, EF||AB
| b | h1 | b | ||||
ΔDCP∼ΔABP cecha kkk w skali | ⇔ | = | stąd | |||
| a | h2 | a |
| a | ||
h2= | *h1 | |
| b |
| y | CS | y | h1 | ||||
= | ⇔ | = | ⇔ | ||||
| a | CK | a | h |
| y | h1 | ||
= | |||
| a | h1+h2 |
| y | h1 | |||||||||||
= | ||||||||||||
| a |
|
| y | b | ||
= | |||
| a | a+b |
| a*b | ||
y= | ||
| a+b |
| a*b | ||
Analogicznie wykażemy, że x= | ||
| a+b |
| 2ab | ||
EF= | ||
| a+b |