| 3x+5 | 4 | |||
a) | − | = | ||
| x2+2 | x−2 |
| 5x−2 | 3x−2x2 | |||
b) | * | |||
| 4x4−9x2 | x+1 |
| (3x+5)(x−2) | 4(x2+2) | 3x2−x−10−4x2−8 | |||
− | = | = | |||
| (x2+2)(x−2) | (x2+2)(x−2) | (x2+2)(x−2) |
| −x2−x−18 | ||
= | ||
| (x2+2)(x−2) |
| 5x−1 | −(2x2−3x) | 1−5x | ||||
b) | * | = | ||||
| (2x2−3x)(2x2+3x) | x+1 | (2x2+3x)(x+1) |
teraz już bede wiedziała jak rozwiązywać