| 2 | 1 | 2x−2−x2+1 | −x2+x+1 | |||||
y= ( | − | ) = | = | |||||
| x2−1 | x−1 | x3−x2−x+1 | x3−x2−x+1 |
| −2x+2 | −2 | −2 | 1 | |||||
lim x−>1 = | = | = | = − | |||||
| 3x2−2x−1 | 6x−2 | 6−2 | 2 |
| 2 | 1 | 2 | 1 | 2 − 1*(x+1) | ||||||
y = | − | = | − | = | = | |||||
| x2−1 | x−1 | (x−1)(x+1) | x−1 | (x−1)(x+1) |
| −(x−1) | 1 | |||
= | = − | |||
| (x−1)(x+1) | x+1 |
Dzięki za ten krótszy sposób, pozdrawiam! 