| 1 | ||
P = | absinγ | |
| 2 |
| c | a | b | ||||
Ale z twierdzenia sinusów mamy | = | = | ||||
| sinγ | sinα | sinβ |
| csinα | csinβ | |||
Czyli a = | oraz b = | |||
| sinγ | sinγ |
| 1 | ||
P = | *a*b*sin(γ) | |
| 2 |
| a | c | c*sin(α) | |||
= | => a = | ||||
| sin(α) | sin(γ) | sin(γ) |
| b | c | c*sin(β) | |||
= | => b = | ||||
| sin(β) | sin(γ) | sin(γ) |
| 1 | c*sin(α) | c*sin(β) | ||||
P = | * | * | *sin(γ) | |||
| 2 | sin(γ) | sin(γ) |
| c2*sin(α)*sin(β) | ||
P = | c.n.d. | |
| 2*sin(γ) |