Wiedząc że log_{a}d=5 log_{b}d=3 log_{c}d=6 oblicz log_{abc}d
Iz_A: Wiedząc że logad=5 logbd=3 logcd=6 oblicz logabcd
3 mar 16:38
Janek191:
log
a d = 5 ⇒ d = a
5 ⇒ a = d
15
log
b d = 3 ⇒ d = b
3 ⇒ b = d
13
log
c d = 6 ⇒ d = c
6 ⇒ c = d
16
więc
a*b*c = d
15 * d
13* d
16 = d
710
zatem
| | 10 | | 10 | |
loga b c d = log d710 d = |
| logd d = |
| |
| | 7 | | 7 | |
3 mar 17:05