równania logarytmiczne
czarnamagia: (2logx−1)logx=3
5(log2 x)2=2+log2 x9
(log4 (x+2))2 =9
logx+ log0,1 x2 =1
23 lut 15:51
czarnamagia: help me!
23 lut 17:19
pigor: ..., np.
| | logx2 | |
4)log x+log 0,1x2=1 i x>0 ⇒ log x+ |
| =1 ⇔ |
| | log0,1 | |
| | 2logx | | 2logx | |
⇔ log x+ |
| =1 ⇔ log x+ |
| =1 ⇔ |
| | log10−1 | | −1 | |
⇔ log x− 2logx =1 ⇔ −logx =1 ⇔ logx= −1 ⇔ x=10
−1 ⇔
x=0,1 .
23 lut 17:28