Całka Krzychu: ∫e^x cosx dx

Mila: ∫e^x cosx dx=.. [ cosx=u, −sinx dx=du, dv=e^x dx , v=e^x ] =e^x cosx+∫(e^xsinx)dx= [ sinx=u, cosx dx=du, dv=e^x dx, v=e^x ] =e^x cosx+e^x*sinx−∫e^xcosx dx⇔ 2∫e^x cosx dx=e^x cosx+e^x*sinx⇔

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∫ex cosx dx=		ex*(cosx+sinx)
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