| sin(x−1) | ||
lim x→1 | ||
| 1−cos(x) |
| 0 | ||
PO podstawieniu mam [ | ] | |
| 0 |
| sin(x−1) | (sin(x−1))' | |||
lim x→1 | = lim x→1 | |||
| 1−cos(x) | (1−cos(x))' |
| cos(x−1) | cos(0) | 1 | ||||
= limx→1 | = | = | ||||
| 1+sin(x) | 1+1 | 2 |
| sin(x − 1) | 0 | |||
limx→1 | = | = 0 | ||
| 1 − cos(x) | 1 − cos(1) |
| 5^2 | 52 |
| 2^{10} | 210 |
| a_2 | a2 |
| a_{25} | a25 |
| p{2} | √2 |
| p{81} | √81 |
| Kliknij po więcej przykładów | |
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| Twój nick | |